2(1/2)^x-5=-x^2-x+4

Solution for 2(1/2)^x-5=-x^2-x+4 equation:

2(1/2)^x-5=-x^2-x+4

We move all terms to the left:

2(1/2)^x-5-(-x^2-x+4)=0


Domain of the equation: 2)^x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(-x^2-x+4)+2(+1/2)^x-5=0

We get rid of parentheses

x^2+x+2(+1/2)^x-4-5=0

We multiply all the terms by the denominator


x^2*2)^x+x*2)^x+2(+1-4*2)^x-5*2)^x=0

We add all the numbers together, and all the variables

x^2*2)^x+x*2)^x+2(-7)^x-5*2)^x=0

Wy multiply elements

8x^5=0

We do not support expression: x^5